How can i extract from string only last number which should be "5"?
var str = "1000040928423195 points added to your balance";var str = parseInt(str);
var lastNum = str.substr(str.length - 1);
console.log(lastNum);
var str = "1000040928423195 points added to your balance";
var lastNumber = str.replace(/\D/g,'');
lastNumber = lastNumber.substring(lastNumber.length - 1);
console.log(lastNumber);
Just add toString() after parseInt
var str = "1000040928423195 points added to your balance";
var str = parseInt(str).toString();
var lastNum = str.substr(str.length - 1);
console.log(lastNum);
Use a regex like /\d+(\d)/
var str = "1000040928423195 points added to your balance";
str.match(/\d+(\d)/)[1]
After your second line, str
isn't a string any more; it is an integer. As such, you can extract the last digit with str % 10
; if necessary, convert that to a string.
Try parsing it with a Regular Expression like so :)
string = "120394023954932503 fdsaf fdsaf dasfasd";
regex = /([0-9]*)/g;
match = regex.exec(string);
last_num = match[0].substr(match[0].length - 1);
console.log(last_num);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="string_val"></div>
Use the regex \d+(\d)
to match multiple digits followed by a digit.
\d
will occupy as many as possible, where (\d)
will match the last.
Then get the last number from the first group [1]
.
var str = "1000040928423195 points added to your balance";
var match = /\d+(\d)/g.exec(str)[1];
console.log(match);
var digit = /.*(\d)/.exec("awoo123awoo")[1];
3