``b=int(1)if b == 1:b=2c = "on my thumb"elif b== 2:b=3c = "on my shoe"elif b== 3:b=4c = "on my knee"elif b== 4:b+1c = "on my door"elif b== 5:b+1c = "on my hive"elif b== 6:b+1c = "on my sticks"elif b== 7:b+1c = "up in heaven"elif b== 8:b+1c = "on my gate"elif b== 9:b+1c = "on my spine"else:c = "once again"for r in range(10):print("This old man, he played one He played knick-knack " + c +" Knick-knack paddywhack, give your dog a bone This old man came rolling home")b+1``

Relatively new to coding so I don't really know what I am doing, but I am trying to get c to change every new time that r is printed....so that IT completes the old nursery rhyme. I am coding this in python...

``````parts = ["on my thumb", "on my shoe", ...]
numerators = ["one", "two", "three", ...]

for num, part in zip(numerators, parts):
print "This old man, he played " + num
print "He played knick-knack " + part
print "This old man came rolling home"
``````

Just store your strings in an array or list

``````lines = ["on my thumb", "on my shoe", "...."....]
``````

and then iterate over that array (or list ) with the help of a for loop in c#-ish syntax:

``````foreach(line in lines)
{
print("bla" + line + "blubb");
}
``````

Maybe something like this:

``````string b[10] = {"on my thumb","on my shoe","on my knee","on my door","on my hive","on my sticks","up in heaven","on my gate","on my spine","once again"};

for (i=0; i<b.length; i++) {
print("This old man, he played one He played knick-knack " + b[i] +" Knick-knack paddywhack, give your dog a bone This old man came rolling home.\n");
}
``````

Since those values will not change you can create a static array to hold the values and then you can cycle through the contents while displaying the result.

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