问题描述:

I have the following code which works fine and creates the grid with 4 columns:

 $("#"+GRID).jqGrid({

url:'ajax.htm',

datatype: 'json',

mtype: 'POST',

jsonReader: { repeatitems : false, cell:"", id: "id", userdata: "jsonModel", root: "rows" },

postData: {

ajaxRequest: document.helper.getPageName(),

screenMode: 'getList'

},

colNames:[

'id'

'listname',

'customer'.

'employee'.

'sum'

],

colModel:[

{name:'id', index:'id', editable:false, hidden: true},

{name:'listname', index:'id', editable:false, hidden: true},

{name:'customer', index:'customerColumn', editable:false, sortable:true},

{name:'employee', index:'employeeColumn', editable:false, sortable:true},

{name:'sum', index:'sum', editable:false, sortable:true}

],

autowidth:true,

shrinkToFit:true,

rownumbers:true,

pager:$('#'+GRID_PAGER),

sortname: 'listname',

sortorder: "desc",

loadonce: true,

rowNum:30,

rowList:[10, 30, 50],

viewrecords:true,

gridComplete:function () {

var data = $("#"+GRID).getGridParam('userData');

})

This code have no subgrids.

Is it posible to edit this, so the grid will have only columns 'id' and 'listname', and on subgrid are 'customer','employee','sum'.

Does subgrid needs another ajax call?

I read that the following lines should be added

subGrid: true,

subGridRowExpanded: function (subGridId, rowId) {}

网友答案:

http://trirand.com/blog/jqgrid/jqgrid.html see grid as subgrid demo, it is in the advanced tab.

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