问题描述:

I've searched for solutions to this problem but couldn't find anything that seems to address it in my case. I'm getting the above exception from a UITapGestureRecognizer.

Here's the simplified code:

import UIKit;

class ViewController : UIViewController, UIScrollViewDelegate

{

@IBOutlet weak var scrollView:UIScrollView!;

var imageView:UIImageView!;

override func viewDidLoad()

{

super.viewDidLoad();

... set up imageView/scrollView here ...

let doubleTapRecognizer = UITapGestureRecognizer(target: self, action: "onScrollViewDoubleTapped");

doubleTapRecognizer.numberOfTapsRequired = 2;

doubleTapRecognizer.numberOfTouchesRequired = 1;

scrollView.addGestureRecognizer(doubleTapRecognizer);

}

func onScrollViewDoubleTapped(recognizer:UITapGestureRecognizer)

{

}

}

Can anyone tell what is wrong with this code? It seems all correct to me. I suspect that it has to do with assigning ViewController as delegate to scrollView (or vice versa)? However the ViewController is set as the delegate to scrollView. But maybe it's something else that causes this error?

网友答案:

Try adding a colon to your selector string.

let doubleTapRecognizer = UITapGestureRecognizer(target: self, action: "onScrollViewDoubleTapped:");

As cabellicar123 mentioned, this indicates that the selector takes an argument.

网友答案:

Also try adding a parameter to your method:

...(target: self, action: "yourMethodName:")

func yourMethodName(sender: AnyObject?)
{
    println("Clicked yourMethodName")
}
网友答案:

Maybe could help someone: I had this error because I declared private the selector method:

func setup() {
  let singleFingerTap = UITapGestureRecognizer(target: self, action: "didTapOnViewInteraction:")
  singleFingerTap.numberOfTapsRequired = 1
  self.viewInteraction.addGestureRecognizer(singleFingerTap)
}

private func didTapOnViewInteraction(recognizer: UITapGestureRecognizer) {

}

Removing "private" keyword, all works great!

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