问题描述:

#include<iostream>

using namespace std;

const int vals[] = {0, 1, 2, 3, 4};

int newArray[ vals[2] ]; //"error: array bound is not an integer constant"

int main(){

return vals[2];

}

//returns 2 if erroneous line is removed

Why doesn't this work?

网友答案:

The C++ compiler can only allocate an array with a size known at compile time. If you want to allocated a variable size piece of memory, use the new operator.

网友答案:

Unfortunately you can't do that in standard C++ because vals[2] is not a constant expression! In the coming standard you would have constexpr(implemented in g++ 4.6) to request compile-time evaluation easily:

#include<iostream> 
using namespace std; 

constexpr int vals[] = {0, 1, 2, 3, 4}; 

int newArray[ vals[2] ]; // vals[2] is a constant expression now!

int main(){
    return vals[2];
}
网友答案:

It's possible that the value of a const expression is not even known at compile time. For example, you can initialize a constant with something returned from a function, like

const int size = rand(); // random size

So it is not that constant as you might think

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