问题描述:

how to remove decimal place in shell script.i am multiplying MB with bytes to get value in bytes .I need to remove decimal place.

ex:-

196.3*1024*1024

205835468.8

expected output

205835468

网友答案:

(You did not mention what shell you're using; this answer assumes Bash).

You can remove the decimal values using ${VAR%.*}. For example:

[[email protected]]$ X=$(echo "196.3 * 1024 * 1024" | bc)
[[email protected]]$ echo $X
205835468.8
[[email protected]]$ echo ${X%.*}
205835468

Note that this truncates the value rather than rounds it. If you wish to round it, use printf as shown in Roman's answer.

The ${variable%pattern} syntax deletes the shortest match of pattern starting from tbe back of variable. For more information, read http://tldp.org/LDP/abs/html/string-manipulation.html

网友答案:

Use printf:

printf %.0f $float

This will perform rounding. So if float is 1.8, it'll give you 2.

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