- (BOOL) saveData:(NSString*)registerNumber name:(NSString*)name
department:(NSString*)department year:(NSString*)year;
{
const char *dbpath = [databasePath UTF8String];
if (sqlite3_open(dbpath, &database) == SQLITE_OK)
{
//here syntax error comes..
NSString *insertSQL = [NSString stringWithFormat:@ "insert into studentsDetail (regno,name, department, year) values ("\"%d\",\"%@\", \"%@\", \"%@\")",[registerNumber integerValue],name, department, year];
const char *insert_stmt = [insertSQL UTF8String];
sqlite3_prepare_v2(database, insert_stmt,-1, &statement, NULL);
if (sqlite3_step(statement) == SQLITE_DONE)
{
return YES;
}else {
return NO;
}
sqlite3_reset(statement);
}
return NO;
}
- (NSArray*) findByRegisterNumber:(NSString*)registerNumber
{
const char *dbpath = [databasePath UTF8String];
if (sqlite3_open(dbpath, &database) == SQLITE_OK)
{
NSString *querySQL = [NSString stringWithFormat:"select name, department, year from studentsDetail where regno=\"%@\" ",registerNumber];
const char *query_stmt = [querySQL UTF8String];
NSMutableArray *resultArray = [[NSMutableArray alloc]init];
if (sqlite3_prepare_v2(database,query_stmt, -1, &statement, NULL) == SQLITE_OK)
{
if (sqlite3_step(statement) == SQLITE_ROW)
{
NSString *name = [[NSString alloc] initWithUTF8String:(const char *) sqlite3_column_text(statement, 0)];
[resultArray addObject:name];
NSString *department = [[NSString alloc] initWithUTF8String:(const char *) sqlite3_column_text(statement, 1)];
[resultArray addObject:department];
NSString *year = [[NSString alloc]initWithUTF8String:(const char *) sqlite3_column_text(statement, 2)];
[resultArray addObject:year];
return resultArray;
}else{
NSLog(@"Not found");
return nil;
}
sqlite3_reset(statement);
}
}
return nil;
}

Syntax error at the stage of *insertsql & *querysql.

Here SQL table is created dynamically & inserted values goes on sql table. I have not more knowledge of SQL.