WPF 获得DataGridRow和 DataGridCell的方法

来源:互联网 时间:1970-01-01

原文地址

简介

在WPF中,DataGrid控件并没有提供访问其DataGridRow或者DataGridCell的方法。
因此我们需要自己来编写获取的方法,这其中主要用到了ItemsControl类的一个实例方法:ItemContainerGenerator

实现代码

using System.Windows.Controls;using System.Windows.Controls.Primitives;using System.Windows.Media;namespace Splash.WPF{ public static class DataGridPlus { /// <summary> /// 获取DataGrid控件单元格 /// </summary> /// <param>DataGrid控件</param> /// <param>单元格所在的行号</param> /// <param>单元格所在的列号</param> /// <returns>指定的单元格</returns> public static DataGridCell GetCell(this DataGrid dataGrid, int rowIndex, int columnIndex) { DataGridRow rowContainer = dataGrid.GetRow(rowIndex); if (rowContainer != null) { DataGridCellsPresenter presenter = GetVisualChild<DataGridCellsPresenter>(rowContainer); DataGridCell cell = (DataGridCell)presenter.ItemContainerGenerator.ContainerFromIndex(columnIndex); if (cell == null) { dataGrid.ScrollIntoView(rowContainer, dataGrid.Columns[columnIndex]); cell = (DataGridCell)presenter.ItemContainerGenerator.ContainerFromIndex(columnIndex); } return cell; } return null; } /// <summary> /// 获取DataGrid的行 /// </summary> /// <param>DataGrid控件</param> /// <param>DataGrid行号</param> /// <returns>指定的行号</returns> public static DataGridRow GetRow(this DataGrid dataGrid, int rowIndex) { DataGridRow rowContainer = (DataGridRow)dataGrid.ItemContainerGenerator.ContainerFromIndex(rowIndex); if (rowContainer == null) { dataGrid.UpdateLayout(); dataGrid.ScrollIntoView(dataGrid.Items[rowIndex]); rowContainer = (DataGridRow)dataGrid.ItemContainerGenerator.ContainerFromIndex(rowIndex); } return rowContainer; } /// <summary> /// 获取父可视对象中第一个指定类型的子可视对象 /// </summary> /// <typeparam>可视对象类型</typeparam> /// <param>父可视对象</param> /// <returns>第一个指定类型的子可视对象</returns> public static T GetVisualChild<T>(Visual parent) where T : Visual { T child = default(T); int numVisuals = VisualTreeHelper.GetChildrenCount(parent); for (int i = 0; i < numVisuals; i++) { Visual v = (Visual)VisualTreeHelper.GetChild(parent, i); child = v as T; if (child == null) { child = GetVisualChild<T>(v); } if (child != null) { break; } } return child; } }}

版权声明:随意转载,但请务必附上原文地址



相关阅读:
Top